Question

Two bodies M and N of equal masses are suspended from separate massless spring of spring constants k1 and k2 respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of variation of M to that of N is?

(a) k1/k2

(b) √(k1/k2)

(c) k2/k1

(d) √(k2/k1)

Answer 1

Correct option is (d) √(k2/k1)

To explain: vmax (A)=vmax (B)

ω1 A1=ω2 A2

√(k1/m)×A1=√(k2/m)×A2

A1/A2 = √(k2/k1).