Correct Answer - Option 3 :
\(\sum \frac{nNL}{AE}\)
Explanation:
From the virtual work principle, we know that
External virtual work = Internal virtual work
When the external virtual loads are multiplied by the real displacement, we get the external virtual work.
If a unit load virtual load produces internal loading equal to ni in various members and the real displacements of the member is dli,
then the internal virtual work done is w.
w = ∑ ni × dli.
Thus, if the virtual load at any point is 1 and the displacement at that point due to external effects is Δ then,
Virtual load × real displacement = Virtual load × Real displacement
1 × Δ = ∑ ni × dli
∴ dli = \(\frac{{{N_i}{L_i}}}{{{A_i}{E_i}}}\) = Change in length of any member due to external load
Hence, from the virtual work principle, we have
Δ = \(\mathop \sum \limits_{i = 1}^n {n_i} \times \frac{{{N_i}{L_i}}}{{{A_i}{E_I}}}\)