Correct Answer - Option 2 : 1
Given:
\(\dfrac{1}{√{3}-2}×\dfrac{1}{√{3}+2}×\dfrac{1}{√{5}+√{6}}×\dfrac{1}{√{5}-√{6}}\)
Formula used:
(a - b)(a + b) = a2 - b2
Calculation:
According to the question,
⇒ \(\dfrac{1}{√{3}-2}×\dfrac{1}{√{3}+2}×\dfrac{1}{√{5}+√{6}}×\dfrac{1}{√{5}-√{6}}\)
⇒ {1/(√32 - 22)} × {1/{√52 - √62}}
⇒ 1/-1 × 1/-1
⇒ 1
∴ The value of \(\dfrac{1}{\sqrt{3}-2}\times\dfrac{1}{\sqrt{3}+2}\times\dfrac{1}{\sqrt{5}+\sqrt{6}}\times\dfrac{1}{\sqrt{5}-\sqrt{6}}\) is 1.