To solve the above Question, we have to first find the total resistance of the circuit.
Here we find that R1 and R2 are in parallel and their combined resistance R’ is given by R’= 10 × 40/10+40 = 8Ω
Also, the resistances of 30Ω, 20Ω and 60Ω are in parallel and their combined resistance R” is given by
1/R” = 1/30 + 1/20 + 1/60 = 2 + 3 + 1/60 = 6/60
R” = 60/6 = 10Ω
Now, R’ and R” are in series and their combined resistance R is given by.
R = R’ + R” = 8Ω + 10Ω = 18Ω
.’. Total resistance in the circuit = 18Ω