Question

The peak value of AC through a resistor of 100 Ω is 2A If the frequency of AC is 50Hz, find the heat produced in the resistor in one cycle.

Answer 1

Data: R = 100 Ω, ⁱ₀ = 2A, f = 50 Hz

H = \(\cfrac{ri^2_0}{2f}\) = \(\cfrac{100(2)^2}{2(50)}\) = 4 J

This is the required quantity.