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In `triangleABC, sin((A)/(2))sin((B)/(2))sin((C)/(2))=`

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in Trigonometry by (123k points)
In `triangleABC, sin((A)/(2))sin((B)/(2))sin((C)/(2))=`
A. `(A(triangleABC))/(abc)`
B. `(A(triangleABC))/(abcs)`
C. `(A(triangleABC)^(2))/(abc)`
D. `(A(triangleABC)^(2))/(abcs)`
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Correct Answer - D
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