Question

Let a triangle ABC be inscribed in the circle x² - √2 (x + y) + y² = 0 such that ∠BAC = π/2. If the length of side AB is √2 , then the area of the ΔABC is equal to:

(A) (√2 + √6) / 3

(B) (√6 + √3) / 2

(C) (√3 + √3) / 4

(D) (√6 + 2√3) / 4

Answer 1

Radius of given circle is 1.