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Vectors A = 2i˄ + 2j˄ – k˄ and B = 2i˄ – j˄ – 2k˄ Find 3A – 2B 

(A) 2i˄ + 7j˄ + k˄ 

(B) 2i˄ + 8j˄ – k˄ 

(C) 2i˄ + 8j˄ + k˄ 

(D) i˄ + 7j˄ + k˄

1 Answer

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Best answer

Correct option: (C) 2i˄ + 8j˄ + k˄

Explanation:

3A – 2B = 3(2i˄ + 2j˄ – k˄) – 2(2i˄ – j˄ – 2k˄)

= 6i˄ + 6˄ – 3k˄ – 4i˄ + 2j˄ + 4k˄

= 2i˄ + 8j˄ + k˄   

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