Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
2.2k views
in Kinematics by (76.5k points)
recategorized by

Vectors A = Pi˄ – 2Pj˄ – k˄ and Vector B = – 3i˄ + 2j˄ – 14k˄ are perpendicular to each other. Then p = … 

(A) 3 

(B) 4 

(C) 2 

(D) 1

1 Answer

+1 vote
by (71.3k points)
selected by
 
Best answer

Correct option: (C) 2

Explanation:

A ⊥ B 

A ∙ B = 0

(Pi˄ – 2Pj˄ – k˄ ( 3i˄ + 2j˄ – 14k˄) = 0

∴ – 3P  4P + 14 = 0

 P = 2 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...