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The ionization energy of hydrogen atom is 13.6 eV. The ionization energy of helium atom would be

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The ionization energy of hydrogen atom is 13.6 eV. The ionization energy of helium atom would be 

(A) 27.2 eV 

(B) 13.6 eV 

(C) 54.4 eV 

(D) 6.8 eV

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1 Answer

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Best answer

The correct option is (C) 54.4 eV.

Explanation:

Ionization energy of atom = E = [(13.6z2) / n2] eV

for helium, z = 2

 ∴ Ionization energy = E = [(13.6 × (22) / (1)2] = 54.4 eV.

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