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Solve the differential equation:

\(ye^\frac{x}{y}\)dx = \((ye^\frac{x}{y} +{\ y^2})\)dy, (y ≠ 0).

1 Answer

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Best answer

On integrating we get, ∫ ev dv = ∫ dy ⇒ ey = y + c

⇒ ex/y = y + c

where 'c' is an arbitrary constant of integration.

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