From the given information, calculate enthalpy of formation of 2 moles of C6H6(l) at 25°C.
Given:
ΔcH(C6H6(l)) = –3264.6 kJ/mol
ΔcH(C(s)) = –393.5 kJ/mol
ΔfH(H2O(l)) = –285.83 kJ/mol
(1) –124.5 kJ/mol
(2) –46.11 kJ/mol
(3) 46.11 kJ/mol
(4) 124.5 kJ/mol