m1 > m2
तब प्रश्नानुसार \(\frac{1}{2}m_1v_1^2=\frac{1}{2}m_2v_2^2\)
\(\frac{m_1}{m_2}=(\frac{v_2}{v_1})^2\)
अर्थात् (m1v1) v1 = (m2v2) v2
अर्थात् p1v1 = p2v2
\(\frac{v_1}{v_2}=\sqrt{(\frac{m_2}{m_1})^2}=\frac{p_1}{p_2}\)
किन्तु m1 > m2 v2 > v1
अर्थात् p1 > p2