Orbital angular momentum for d-electron will be: (a) 6h/ 2π (b) √6h/2π

Question

Orbital angular momentum for d-electron will be: 

\((a)\ \frac{6h}{2\pi}\)

\((b)\ \frac{\sqrt{6h}}{2\pi}\)

\((c)\ \frac{12h}{2\pi}\)

\((d)\ \frac{14h}{2\pi}\)

Answer 1

Correct option is : \((b)\ \frac{\sqrt{6h}}{2\pi}\)