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In a thermodynamic process on an ideal monatomic gas, the infinitesimal heat absorbed by the gas is given by TΔX, where T is temperature of the system and ΔX is the infinitesimal change in a thermodynamic quantity

X of the system. For a mole of monatomic ideal gas x = - 3/2R in(T/TA) + R in (V/VA). Here, R is gas constant, V is volume of gas, TA and VA are constants. 

The List-l below gives some quantities involved in a process and List-II gives some possible values of these quantities.

List- List-II
(l) Work done by the system in process 1 → 2 → 3 (P) 1/3RT0 In 2
(II) Change in internal energy in process 1 → 2 → 3  (Q)  1/3 RT0
(III) Heat absorbed by the system in process 1 → 2→ 3  (R)  RT0
(IV) Heat absorbed by the system in process 1 → 2 (S)  RT0
(T) 1/3 RT0(3 + in2)
(U) 5/6RT0

If the process carried out on one mole of monatomic ideal gas is as shown in figure in the PV-diagram with P0V0 = 1/3RT0, the correct match is,

(A)  I  Q, II  R, III  S, IV  U

(B)  I  Q, II  S, III  R, IV  U

(C)  I  S, II  R, III  Q, IV  T

(D)  I  Q, II  R, III  P, IV  U

1 Answer

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Best answer

Correct option (A) I  Q, II  R, III  S, IV  U

Explanation:

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