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A n–p–n transistor is used as an amplifier in (a) common–base (b) common–emitter configuration. The voltage gain in two cases is A1 and A2 respectively. The phase difference between input and output in the two cases is δ1 and δ2 respectively which of the following is correct?

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Best answer

Correct option: (2)

Explanation: 

The common base configuration in an amplifier, the output and input are in phase i.e. δ1 = 0. However in common–emitter amplifier output is out of phase with input and output lags behind input i.e. δ2 = -π.

The voltage gain in common–emitter configuration is more than in common–base configuration i.e. A1 > A2.

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