Question

How much mass is there approximately in 1 L of mercury (Hg)? 

Answer 1

A volume of 1 L equals 0.001 m3, 

 the density is in the range of 10000 kg/m³ 

so we get

m = ρV = 10 000 kg/m³ × 0.001 m³ = 10 kg

A more accurate value  is ρ

= 13580 kg/m³. 

For the air  1 kg/m³ so we get

m = ρV = 1 kg/m³ × 0.001 m³ = 0.001 kg

 A more accurate value is ρ

= 1.17 kg/m³ at 100 kPa, 25°C.