Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.9k views
in Physics by (63.7k points)
retagged by

एक वैद्युत द्विध्रुव 1.0 x 10-6 कूलॉम परिमाण तथा विपरीत प्रकृति के दो वैद्युत आवेशों से बना है। इन आवेशों के बीच की दूरी 2.0 सेमी है। इस द्विध्रुव को 1.0 x 105 न्यूटन/कूलॉम की बाह्य वैद्युत-क्षेत्र तीव्रता में रखा गया है। द्विध्रुव पर अधिकतम बल-आघूर्ण का मान निकालिए। 

1 Answer

0 votes
by (69.5k points)
selected by
 
Best answer

τmax = pE = (q x 2l) x E 

= (1.0 x 10-6 x 2.0 x 10-2) (1.0 x 105

= 2.0 x 10-3 न्यूटन-मीटर

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...