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यदि पृथ्वी के किसी स्थान पर पृथ्वी के चुम्बकीय क्षेत्र के ऊर्ध्वाधर घटक का मान क्षैतिज घटक के मान का √3 गुना हो तो उस स्थान पर नति कोण का मान क्या होगा? 

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माना उर्ध्वघटक V = B sin θ 

क्षैतिज घटक H = B cos θ 

V = H tan θ प्रश्नानुसार, V√3 = H 

अतः V = V√3 tan θ

tan θ = 1/√3 = tan 30°

θ = 30° 

अतः नति कोण θ = 30°

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