(1) Let A BCD and EFGH are perpendicular path
AB = 125 m
BC = 10 m
∴ Area of ABCD
= 125 x 10
= 1250 sq. m
∴ Again EF = 95 m
and FG = 10 m
∴ Area of EFGH = 95 x 10
= 950 sq. m
PQRS is common area in both the paths
∴ Area of PQRS = 10 x 10 = 100 sq. m
Area of both paths = Area of ABCD + Area of EFGH – Area of PQRS
= (1250 + 950 – 100) = (2200 – 100)
= 2100 sq. m
Expenditure on putting soil on 1 m2 = ₹80
Expenditure on putting soil on 2100 sq. m = 2100 x 80 = ₹1,68,000
(2) Area of rectangular park
= 125 x 95 = 11875 sq. m
Area of putting grass = Area of LMNO – Area of both paths
= 11875 – 2100 = 9775 sq. m