Question

In Dumas' method for the estimation of nitrogen 0.3 g of an organic compound gave 50 ml of nitrogen at 300 K temperature and 715 mm pressure. Calculate the percentage composition of nitrogen in organic compound. [Aqueous tension at 300 K 15 mm]

Answer 1

Volume of nitrogen at 300 K and 715 mm

Pressure = 50 ml

We know,

\(\frac{P_1V_1}{T_1}\)= \(\frac{P_2V_2}{T_2}\)

Using (At STP), Volume of nitrogen at STP,

V₁ = \(\frac{P_2V_2}{T_2}\) x \(\frac{T_1}{T_2}\)

= \(\frac{700\times50}{300}\) x \(\frac{273}{760}\)

= 41.91 ml