Question

Assign the oxidation number to Cr in K₂Cr₂O₇.

Answer 1

Let the oxidation number of Cr be x

Sum of the oxidation number of various atoms in K₂Cr₂O₇

= 2 × (+1) + 2x + 7 × (– 2) = 0

= 2 + 2x – 14 = 2x – 12 = 0

x = \(\frac{12}{2}\) = +6

\(\therefore\)Oxidation number of Cr in K₂CrO₇ = +6