(A + B)’s 1 day’s work = 1/10……….(1)
(B + C)’s 1 day’s work = 1/12……….(2)
(A + C)’s 1 day’s work = 1/15……….(3)
(l) + (2) + (3) ⇒
[A + B + B + C + A + C]’s 1 day work
= 1/10 + 1/12 + 1/15
(2A + 2B + 2C)’s 1 day work = (6+5+4)/60
2(A + B + C)’s 1 day work = 15/60
(A + B + C)’s 1 day’s work = 1/(4×2) = 1/8
∴ A + B + C work together to finish the work in 8 days.