Question

Calculate the amount of water (g) produced by the combustion of 16 g of methane.

Answer 1

The balanced equation for combustion of methane is–

1 mole of CH₄(g) gives 2 mol of H₂O

2 moles of water (H₂O) = 2 × (2 + 16)

= 2 x 18 = 36 g

1 mole H₂O = 18 g H₂O \(\Rightarrow\) \(\frac{18\,g\,H_2O}{1\,mol\,H_2O}\)

\(\therefore\) Amount of water produced by the combustion

Of 16 g of methane = 2 mol H₂O x \(\frac{18\,g\,H_2O}{1\,mol\,H_2O}\)

= 2 x 18 g H₂O

= 36 g H₂O