1. Electronic configuration of N atom is 1s2 2s2 2p3
2. Electronic configuration of O atom is 1s2 2s2 2p4
3. Electronic configuration of NO molecule is σ1s2 σ*1s2 σ2s2 σ*2s2 π2px2 π2py2 π2pz2 π*2px1
4. Bond order = \(\frac{N_b-N_a}{2}\) = \(\frac{10-5}{2}\) = 2.5
5. NO molecule has one unpaired electron, hence it is paramagnetic