Weight of organic compound = 0.20 g
Volume of sulphuric acid taken = 15 ml
Strength of sulphuric acid taken = \(\frac{N}{20}\) = 0.05 N
Percentage of nitrogen = \(\frac{14\times NV}{1000\times10}\) x 100
= \(\frac{14\times0.05\times 15}{1000\times0.20}\) x 100
= \(\frac{1050}{200}\) = 5.25
% of nitrogen = 5.25%