Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
23.8k views
in Physics by (245 points)
edited by

Use ampere's circuital law to derive the formula for the magnetic field due to an infinitely long straight current carring wire.

Please log in or register to answer this question.

1 Answer

+1 vote
by (15.3k points)

Ampere’s circuital law:

This law states that the line integral of the magnetic field of induction along a closed path in a vacuum is equal to \(\mu_o\) times the total current threading the closed path.

\(\int\vec{B}.d\vec{I}\)\(\mu_oI\)

Magnetic field (of induction) due to an infinitely long current carrying conductor:

Let us consider a long straight wire XY carrying a current I. Let P be a point at a perpendicular distance r from the point O on the wire.

Let us imagine a circular path of radius r, centre O so that the point P lies on the path.

Now, from Ampere’s Circuital law,

\(\int\vec{B}.d\vec{I}\)\(\mu_oI\)

\(\implies\)\(\int\vec{B}.dl\) = \(\mu_oI\) [Since angle between \(\vec{B}\) and \(d\vec{I}\) is zero]

\(\implies\) \({B\int}dl\) = \(\mu_oI\)

\(\implies\) \(B.2πr=μ_0I\) [Since the total length of \(d\vec{I}\) is equal to circumference of the circle considered]

\(\implies\) B = \(\frac{\mu_oI}{2\pi r}\)

which is the required expression for magnetic field of induction due to a long straight current carrying wire.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...