Consider a body of mass m is rotating around the star s in circular path of radius r.
(i) Orbital velocity –
vo = \(\sqrt{\frac{GM}{r}}\) or v ∝ \(\frac{1}{\sqrt r}\)
Orbital Velocity decreases
(ii) Angular velocity \(\frac{2\pi}{T}\)
By Kepler’s III law
T2 \(\propto\) r3 or T2 = Kr3
\(\omega\) = \(\frac{2\pi}{Kr^{\frac{3}{2}}}\) or \(\omega\) \(\propto\) \(\frac{1}{\sqrt{r^3}}\)
Hence, angular velocity decreases.
(iii) Kinetic Energy, K = \(\frac{1}{2}\)m\(\frac{GM}{r}\) or K \(\propto\) \(\frac{1}{r}\)
Hence K, decreases on increasing the radius.
(iv) Gravitational Potential Energy,
U = \(-\frac{GMm}{r}\)
or U \(\propto\) \(\frac{-1}{2}\)
So, on increasing radius of circular orbit the U increases.
(v) Total energy,
E = K + U = \(\frac{GMm}{2r}+\big(-\frac{Gmm}{r}\big)\)
E = −\(\frac{GMm}{2r}\)
So, increasing the radius, E will also be increased.
(vi) Angular momentum, L = mvr = mr\(\sqrt{\frac{GM}{r}}\)
L = m\(\sqrt{GMr}\) or L \(\propto\) \(\sqrt r\), increases