In the figure, the shaded region OABC is the feasible region. Here the region is bounded.
O(0,0) , A(2,0) ,\(B(\frac{20}{19},\frac{45}{19})\),C(0,3)
Given; Z = 5x + 3y
Corner points |
Value of Z |
O |
Z = 0 |
A |
Z = 5(2)+3(0) = 10 |
B |
Z = 5\(\frac{20}{19} + 3 (\frac{45}{19})=\frac{235}{19}\) |
C |
Z = 5(0)+3(3) = 9 |
Since maximum value of Z occurs at B, the solution is Z = 10,9