(a) The angle between the vectors a and b such that ​|vec a| = |vec b| = √2 bar a. bar b = 1 is

Question

(a) The angle between the vectors \(\bar a \,and\, \bar b\) such that |\(\vec a\) |=|\(\bar b\)| = \(\sqrt 2\) 

\(\bar a.\bar b\)= 1 is

 (i) \(\frac{π}{2}\) 

(ii) \(\frac{π}{3}\) 

(iii) \(\frac{π}{4}\)

(iv) 0

(b) Find the unit vector along \(\bar a - \bar b\)  where \(\bar a\) = i + 3j – k and  \(\bar b\)  3i + 2j + k

Answer 1

= \(\frac{-2i + j -2k}{3}\)