1. fof(x) = f(f(x)) = f(\(\frac{2x-3}{x-2}\))
2. Following satisfies the condition f-1 ≠ f:
(a) f : R – {0} → R – {0}, f(x) = \(\frac{1}{x}\)
(b) f :R → R, f(x) = -x
The graph of functions in (a) and (b) symmetric with respect to the line y = x.
The function in (d) we have already shown that fof (x) = x. So the answer is (c)
f : R – {-1} → R – {-1}, f(x) = \(\frac{x}{x+1}\)