(i)
For a large magnifying power, fo should be large and fe should be small.
For a higher resolution, the diameter of the objective should be large.
Note for students: You may draw refractive or reflective telescope.
(ii) \(\frac{1}{v_o}-\frac{1}{u_o}=\frac{1}{f_o}\)
\(\frac{1}{v_o}=\frac{1}{f_o}+\frac{1}{u_o}\)
\(\frac{1}{v_o}=\frac{1}{1.25}-\frac{1}{2.5}\)
\(\frac{1}{v_o}=\frac{1}{2.5}⇒v_o=2.5cm\)
If the final image is at infinity it means image from objective lens would be at focal length of eye piece.
Additionally, this is 2.5 cm away from objective lens.
Hence tube length in this case = 2.5 cm + 5.0 cm = 7.5 cm