Let
A = B, then A ∪ B = A and A ∩ B = A
A ∪ B = A ∩ B
Thus, A = B …(i)
Conversely, let
A ∪ B = A ∩ B
Now, let
x ∈ A
x ∈ (A ∪ B ) [∴ A ∪ B = A ∩ B]
x ∈ (A ∩ B )
(x ∈ A and x ∈ B)
x ∈ B
A ⊆ B …(ii)
Now, let
y ∈ A
y ∈ A ∪ B
y ∈ A ∩ B[∴ A ∪ B = A ∩ B]
y ∈ A and y ∈ B
y ∈ A
∴ B ⊆ A …(iii)
From equations (ii) and (iii), we get A = B