1. The given lines are
The dr’s of (1) are 2, 2, 3 and dr’s of (2) are -3, 2, 5.
2. The angle between (1) and (2) is given by
3. Let a, b, c be the dr’s of the line perpendicular to lines (1) and (2).
∴ 2a + 2b + 3c = 0, -3a + 2b + 5c = 0
Solving by the rule of cross-multiplication, we get
∴ dr’s of the required line are 4, -19, 10 and the line passes through (2, 1, 3).
∴ Equation of the required line is
\(\frac{x-2}{4}= \frac{y-1}{-19}= \frac{z-3}{10}.\)
