1. In the figure the shaded region OABC is the fesible region. Here the region is bounded. The corner points are O(0, 0), A(30, 0), B(20, 30), C(0, 50).
Given; Z = 60x + 15y
Corner points |
Value of Z |
O |
Z = 0 |
A |
Z = 60(30) +15(0) = 1800 |
B |
Z = 60(20) + 15(30) = 16500 |
C |
Z = 60(0) + 15(50)=750 |
Since maximum value of Z occurs at A, the solution is Z = 1800, (30, 0).