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Given that 5n-5 is divisible by 4 ⊂ N. Prove that 2.7n + 3.5n−5 is multiple of 24.

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Let P(n) ∶ 2.7n + 3.5n − 5 is a multiple of 24.

Step 1: P(1) ∶ 2.7n + 3.51 − 5 = 14 + 15 − 5 = 24,

Which is a multiple of 24.

∴ P(1) is true.

Step 2: Let it be true for some k ∈ N, i.e,.

P(k): 2.7k + 3.5k − 5 = 24λ for some λ ∈ N.  ...(i)

Step 3: To prove that

P(k + 1) ∶ 2.7k+1+3.5k+1−5 is also multiple of 24.

Now, 

2.7k+1+3.5k+1−5

2.7k.7 + 3.5k.5 − 5

7(2.7k) + 5.(3.5k) − 5

7(24λ− 3.5k + 5) + 5.(3.5k) − 5

= 7.24λ − 21.5k + 15.5+ 35 − 5

= 7.24λ − 6(5k−5)

= 7.24λ − 6(4μ)

= 24(7λ − μ)

Which is a multiple of 24. For some λ,μ ∈ N.

∴ P(k + 1) is true whenever P(k) is true

Hence, by Principle of Mathematical Induction

P(n) in true for all n ∈ N.

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