Let the triangle be ABC with vertex A(1, 1) and midpoint of AB is E (– 1, 2), midpoint of AC is F (3, 2). Let (x1 y1) and (x2, y2) be the co-ordinate of B and C respectively. Since E is the midpoint of AB.
\(\therefore (\frac{1+x_1}{2},\frac{1+y_1}{2})=(-1,2)\)
⇒ x1 = − 3, y1 = 3
And F is the midpoint of AC
\(\therefore (\frac{1+x_2}{2},\frac{1+y_2}{2})=(3,2)\)
⇒ x2= 5, y2 = 3
∴ Centroid of the triangle have co-ordinates
\((\frac{1-3+5}{3},\frac{1+3+3}{3})=(1,\frac{7}{3})\)
