Question

(a) Out of (CH₃)₃C – Br and (CH₃)₃C – I, which one is more reactive towards S_N1 and why? 

(b) Write the product formed when p-nitrochlorobenzene is heated with aqueous NaOH at 443 K followed by acidification. 

(c) Why dextro and laevo – rotatory isomers of butan-2-ol are difficult to separate by fractional distillation?

Answer 1

(a) (CH₃)₃C−I is more reactive towards S_N1 than (CH₃)₃C−Br as I⁻ is a better leaving group than Br⁻ .

(b)

 

(c) Dextro and laevo-rotatory isomers of butan-2-ol are difficult to separate by fractional crystallization due to their identical boiling points.