(a) (i) Cannizzaro’s reaction :- Aldehydes which do not contain α-H atom undergo disproportionation when heated with concentrated (50%) NaOH.

(ii) Clemmensen reduction :- The carbonyl group of aldehydes and ketones is reduced to CH2 group on treatment with zinc amalgam and concentrated hydrochloric acid.

(b) Calculation of the empirical formula of the compound :

So, the empirical formula is C5H10O
Empirical formula mass
= (5 × 12) + (10 × 1) + (1 × 16) = 86
Given that molecular mass of the compound = 86
Hence, the molecular formula of the compound is
C5H10O.
The given compound does not reduce Tollens’ reagent, so it is not an aldehyde but the formation of addition compound with sodium hydrogen sulphite indicates it to be a carbonyl compound. Since this compound gives positive iodoform test, so it should contain
group.
On the basis of this information, two possible structures are written as under :

On oxidation, this compound gives ethanoic and propanoic acids which confirm its structure to be I.