Question

(A) HOCl + H₂O₂ → H₃O⁺ + Cl^– + O₂

(B) I₂ + H₂O₂ + 2OH^–→ 2I^– + 2H₂O + O₂ 

Choose the correct option.

(1) H₂O₂ acts as reducing and oxidising agent respectively in equation (A) and (B) 

(2) H₂O₂ acts as oxidising agent in equation (A) and (B)

(3) H₂O₂ acts as reducing agent in equation (A) and (B)

(4) H₂O₂ act as oxidizing and reducing agent respectively in equation (A) and (B)

Answer 1

(3) H₂O₂ acts as reducing agent in equation (A) and (B)

(A) – HOCl + H₂O₂ → H₃O⁺ + Cl^- + O₂

In this equation, H₂O₂ is reducing chlorine from +1 to –1.

(B) I₂ + H₂O₂ + 2OH^–→ 2I^– + 2H₂O + O₂

In this equation, H₂O₂ is reducing iodine from 0 to –1.

In (A) reduction of HOCl occurs so it will be a oxidising agent hence H₂O₂ will be a reducing agent.

In(B) reduction of I₂ occurs so it will be a oxidising agent and H₂O₂ will be a reducing agent.