A charge 'q' is placed at one corner of a cube as shown in figure.The flux of electrostatic field E rthrough the shaded area is :

Question

A charge 'q' is placed at one corner of a cube as shown in figure.The flux of electrostatic field \(\vec E\) through the shaded area is :

(1) \(\frac{q}{4\varepsilon_0}\)

(2) \(\frac{q}{24\varepsilon_0}\)

(3) \(\frac{q}{48\varepsilon_0}\)

(4) \(\frac{q}{8\varepsilon_0}\)

Answer 1

Correct option  is (2) \(\frac{q}{24\varepsilon_0}\)

flux through cube \(=\frac{q}{8\in_0}\)

flux through surfaces ABEH, ADGH, ABCD will be zero

ϕ (EFGH) =ϕ (DCFG) = ϕ (EBCF) = \(\frac{1}3(\frac{q}{8\in_0})\) \(=\frac{q}{24\in_0}\)