Question

In connection with the circuit drawn below, the value of current flowing through 2 kΩ resistor is ...... × 10^–4 A.

Answer 1

Current through 2kΩ resistance

I = \(\frac{5}{2\times 10^3}\)   2.5 × 10^–3 A

I = 25 × 10^–4 A

Answer 2

I=5/2*10^3 

this implies I= 2.5*10^-3

I=25*10^-4