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+2 votes
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The solubility of AgCN in a buffer solution of pH = 3 is x. The value of x is:

[Assume : No cyano complex is formed; Ksp(AgCN) = 2.2 × 10–16 and Ka (HCN) = 6.2 × 10–10]

(1) 0.625 × 10–6 

(2) 1.9 × 10–5 

(3) 2.2 × 10–16 

(4) 1.6 × 10–6

2 Answers

+1 vote
by (36.2k points)
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Best answer

Correct option is (2) 1.9 × 10–5

Let solubility is x

\(AgCN \rightleftharpoons \underset {x} {Ag^+} +\underset {x}{CN^-}\)

\(H^+ + CN^- \rightleftharpoons HCN\)

\(K_{sp} = 2.2 \times 10^{-16}\)

\(K = \frac 1 {K_a} = \frac 1 {6.2\times 10^{-10}}\)

\(K_{sp} \times \frac 1{K_a} = [Ag^+][CN^-] \times \frac{[HCN]}{[H^+][CN^-]}\)

\(2.2 \times 10^{-16} \times \frac1{6.2 \times 10^{-10}} = \frac{[S][S]}{10^{-3}}\)

\(S^2 = \frac{2.2}{6.2} \times 10^{-9}\)

\(S^2 = 3.55 \times 10^{-10}\)

\(S = \sqrt{3.55 \times 10^{-10}}\)

\(S = 1.88 \times 10^{-5}\)

\(S = 1.9\times 10^{-5}\)

+3 votes
by (26.8k points)

(2) 1.9 × 10–5

s = 1.9 × 10–5

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