The value of the integral ∫|sin 2x| dx, x ∈[0 to π] is

Question

The value of the integral \(\int\limits_0^\pi\)|sin 2x| dx is

Answer 1

Answer is 2

Put 2x = t ⇒ 2dx = dt

⇒ \(I=\frac 12\int\limits_0^{2\pi}\)|sin t| dt

\(=\int\limits_0^\pi\)|sin t| dt = 2