Question

Six coins are tossed simultaneously. Find the probability of getting 

i. 3 heads

ii. no heads 

iii. at least one head.

Answer 1

Let p be the probability of getting a head in the toss of a coin.

Then, p = \(\frac{1}{2}\) ⇒ q = 1 - p = \(\frac{1}{2}\)

Let X = Number of successes in the experiment, then X can take the values, 0, 1, 2, 3, 4, 5, 6

Here n = 6. Now by Binomial distribution, we have