Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
1.5k views
in 3D Coordinate Geometry by (30.9k points)
closed by

Find the coordinates of the foot of perpendicular and the length of the perpendicular drawn from the point P (5, 4, 2) to the line

\(\vec{r}=-\hat{i}+3\hat{j}+\hat{k}+\lambda (2\hat{i}+3\hat{j}-\hat{k}).\) Also find the image of P in this line.

1 Answer

+1 vote
by (31.4k points)
selected by
 
Best answer

Given line is

It can be written in cartesian from as

Let Q(\(\alpha, \beta, \gamma\)) be the foot of perpendicular drawn from P(5, 4, 2) to the line (i) and P' (\(x_1, y_1,z_1\)) be the image of P on the line(i)

Parallel vector of line (i) \(\vec{b}=2\hat{i}+3\hat{j}-\hat{k}.\)

[Putting value of \(\alpha, \beta, \gamma\) from (ii)]

Hence the coordinates of foot of perpendicular Q are \((2\times 1-1,\,3\times 1+3,\, -1+1),\) i.e., (1, 6, 0)

\(\therefore\) Length of perpendicular

Also, since Q is mid-point of PP'

Therefore required image is (-3, 8, -2).

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...