The value of cos\((\frac{4\pi}3)\) is \(\frac{-1}2\)
Now,
∴ The question becomes cos–1\((\frac{-1}{2})\)

The range of principal value of cos–1 is [0,π] and cos\((\frac{2\pi}3)=\frac{-1}2\)
Therefore, the value of cos–1(cos\((\frac{4\pi}3)\)) is \(\frac{2\pi}3\)