Question

Let the lengths of intercepts on x-axis and y-axis made by the circle x² + y² + ax + 2ay + c = 0, (a < 0) be \(2\sqrt{2}\) and \(2\sqrt{5},\) respectively. Then the shortest distance from origin to a tangent to this circle which is perpendicular to the line x + 2y = 0, is euqal to :

(1) \(\sqrt{11}\)

(2) \(\sqrt{7}\)

(3) \(\sqrt{6}\)

(4) \(\sqrt{10}\)

Answer 1

Correct answer is (3)

Perpendicular distance from (0, 0)