Given,
A = \(\begin{bmatrix} 1 &2 & 0 \\[0.3em] -1 & 0 & 1 \end{bmatrix}\),
B = \(\begin{bmatrix}1 &0 \\[0.3em] -1 &2 \\[0.3em] 0 & 3 \end{bmatrix}\)and C = \(\begin{bmatrix}1 \\[0.3em] -1 \end{bmatrix}\)


From equation (1) and (2) we get,
A(BC) = A(BC)