![](https://www.sarthaks.com/?qa=blob&qa_blobid=14058772549688198444)
∴ Theoretical amount of given product formed
= \(\frac{273}{140.5}\) x 0.140 0.272 gm
But its actual amount formed is 0.210 gm. Hence, the percentage yield of product.
![](https://www.sarthaks.com/?qa=blob&qa_blobid=955556358872637727)
OR
![](https://www.sarthaks.com/?qa=blob&qa_blobid=7611391544488443143)
![](https://www.sarthaks.com/?qa=blob&qa_blobid=11189975886758010687)
by mol-mol analysis = 10–3 mol.
Theoritical mass of product = 10–3 × 273 = 273 × 10–3 g
Observed mass of product = 210 × 10–3 g
%yield of product = \(\frac{210\times10^{-3}}{273\times10^{-3}}\) x 100 = 76.9% = 77